Overengineered in my view, what is wrong with `x | f` is `f(x)`? Then `x | f | g... | Hacker News

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		sproutini 67 days ago \| parent \| context \| favorite \| on: Working pipe operator today in pure JavaScript Overengineered in my view, what is wrong with `x \| f` is `f(x)`? Then `x \| f \| g` can be read as `g(f(x))` and you're done. I don't see any reason to make it more complicated than that.

xigoi 67 days ago [–]

You can’t make it work like that in current JavaScript.

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