Your question is a bit confusing and ambiguous. I think there are multiple valid answers. Here's a local test of a less ambiguous programming question with "Wizard-Vicuna-30B-Uncensored.ggmlv3.q8_0.bin" on llama.cpp on an M1 Max laptop with 64GiB of RAM.
This model seems roughly on par with GPT-3, maybe GPT-3.5 in some cases.
> Write a function to compute the maximum, minimum, and average of an array of doubles in C.
Here is an example function in C that computes the maximum, minimum, and average of an array of doubles:
```c
void compute_statistics(double arr[], int n) {
double max = arr[0];
double min = arr[0];
double sum = 0.0;
for (int i = 1; i < n; i++) {
if (arr[i] > max) {
max = arr[i];
} else if (arr[i] < min) {
min = arr[i];
}
sum += arr[i];
}
double avg = sum / n;
printf("Maximum: %.2f", max);
printf("Minimum: %.2f", min);
printf("Average: %.2f", avg);
}
```
To use this function, simply call it with the array of doubles and its length as arguments. For example:
```c
double arr[] = {1.0, 2.5, 3.0, 4.0, 5.0};
int n = sizeof(arr) / sizeof(arr[0]);
compute_statistics(arr, n);
```
This will output:
```
Maximum: 5.00
Minimum: 1.00
Average: 3.00
```
Here are some simple logic questions:
> Compute the sum of an array of 512 elements with each element having the value 2.
The sum of an array of 512 elements with each element having the value 2 is 1024.
> Compute the sum of an array of 512 elements with each element having the value 3.
The sum of an array of 512 elements with each element having the value 3 is 1536.
This model seems roughly on par with GPT-3, maybe GPT-3.5 in some cases.
> Write a function to compute the maximum, minimum, and average of an array of doubles in C.
Here is an example function in C that computes the maximum, minimum, and average of an array of doubles:
```c void compute_statistics(double arr[], int n) { double max = arr[0]; double min = arr[0]; double sum = 0.0; for (int i = 1; i < n; i++) { if (arr[i] > max) { max = arr[i]; } else if (arr[i] < min) { min = arr[i]; } sum += arr[i]; } double avg = sum / n; printf("Maximum: %.2f", max); printf("Minimum: %.2f", min); printf("Average: %.2f", avg); } ```
To use this function, simply call it with the array of doubles and its length as arguments. For example:
```c double arr[] = {1.0, 2.5, 3.0, 4.0, 5.0}; int n = sizeof(arr) / sizeof(arr[0]); compute_statistics(arr, n); ```
This will output:
``` Maximum: 5.00 Minimum: 1.00 Average: 3.00 ```
Here are some simple logic questions:
> Compute the sum of an array of 512 elements with each element having the value 2.
The sum of an array of 512 elements with each element having the value 2 is 1024.
> Compute the sum of an array of 512 elements with each element having the value 3.
The sum of an array of 512 elements with each element having the value 3 is 1536.
Not bad.